24x^2-42x-12=0

Solution for 24x^2-42x-12=0 equation:

24x^2-42x-12=0

a = 24; b = -42; c = -12;
Δ = b2-4ac
Δ = -422-4·24·(-12)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-54}{2*24}=\frac{-12}{48}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+54}{2*24}=\frac{96}{48}
=2
$